If 10^{-6} M HCl is diluted 100 times,its p | vedclass

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(C) Initial concentration of $HCl = 10^{-6} \ M$. After $100$ times dilution,the new concentration of $HCl = \frac{10^{-6}}{100} = 10^{-8} \ M$. In ve

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$6.95$

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(C) Initial concentration of $HCl = 10^{-6} \ M$. After $100$ times dilution,the new concentration of $HCl = \frac{10^{-6}}{100} = 10^{-8} \ M$. In very dilute solutions,the contribution of $H^+$ ions from water cannot be ignored. Total $[H^+] = [H^+]_{HCl} + [H^+]_{water} = 10^{-8} + 10^{-7} \ M$. $[H^+] = 10^{-8} + 10 	imes 10^{-8} = 11 	imes 10^{-8} \ M$. $pH = -\log[H^+] = -\log(11 	imes 10^{-8}) = 8 - \log(11) = 8 - 1.0414 = 6.9586 \approx 6.95$.

If $10^{-6} \ M \ HCl$ is diluted $100$ times,its $pH$ will be:

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