(C) For a salt of type $A_xB_y$,the solubility product $K_{sp}$ is given by $K_{sp} = x^x y^y S^{(x+y)}$.For $M_2X$ $(x=2, y=1)$: $K_{sp} = 2^2 \times

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$K_{sp}(M_2X) = K_{sp}(QY_2) > K_{sp}(PZ_3)$

(C) For a salt of type $A_xB_y$,the solubility product $K_{sp}$ is given by $K_{sp} = x^x y^y S^{(x+y)}$.For $M_2X$ $(x=2, y=1)$: $K_{sp} = 2^2 \times 1^1 \times S^{(2+1)} = 4S^3$.For $QY_2$ $(x=1, y=2)$: $K_{sp} = 1^1 \times 2^2 \times S^{(1+2)} = 4S^3$.For $PZ_3$ $(x=1, y=3)$: $K_{sp} = 1^1 \times 3^3 \times S^{(1+3)} = 27S^4$.Since $S K_{sp}(PZ_3)$.

Class 11 Chemistry 6-2.Equilibrium-II (Ionic Equilibrium)Solubility product

Difficult

If the solubility of salts $M_2X$,$QY_2$,and $PZ_3$ is the same $(S < 1)$,what is the relationship between their solubility products $(K_{sp})$?

A
$K_{sp}(M_2X) = K_{sp}(QY_2) < K_{sp}(PZ_3)$
B
$K_{sp}(M_2X) > K_{sp}(QY_2) = K_{sp}(PZ_3)$
C
$K_{sp}(M_2X) = K_{sp}(QY_2) > K_{sp}(PZ_3)$
D
$K_{sp}(M_2X) > K_{sp}(QY_2) > K_{sp}(PZ_3)$

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If the solubility of salts $M_2X$,$QY_2$,and $PZ_3$ is the same $(S < 1)$,what is the relationship between their solubility products $(K_{sp})$?

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How many grams of $CaC_2O_4$ will dissolve in distilled water to make one litre of saturated solution (in $g$)? (Solubility product of $CaC_2O_4$ is $2.5 \times 10^{-9} \ mol^2 \ L^{-2}$ and its molecular weight is $128$)

How many grams of $CaC_2O_4$ will dissolve in distilled water to make $1 \, L$ of a saturated solution (in $, g$)? The solubility product $(K_{sp})$ of $CaC_2O_4$ is $2.5 \times 10^{-9} \, mol^2 \, L^{-2}$ and its molar mass is $128 \, g \, mol^{-1}$.

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