For the reaction HCOO^{-} + H_2O rightlefthar | vedclass

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Question

(B) The given reaction represents the hydrolysis of the formate ion $(HCOO^-)$,which is the anion of a weak acid $(HCOOH)$ and a strong base $(NaOH)$.

Vedclass · Accepted Answer

$h = \sqrt{\frac{K_h}{C}}$

Vedclass · Answer

(B) The given reaction represents the hydrolysis of the formate ion $(HCOO^-)$,which is the anion of a weak acid $(HCOOH)$ and a strong base $(NaOH)$.For the hydrolysis of a salt of a weak acid and a strong base,the degree of hydrolysis $(h)$ is related to the hydrolysis constant $(K_h)$ and the concentration $(C)$ of the salt solution by the formula:$K_h = C h^2$Rearranging this for $h$,we get:$h = \sqrt{\frac{K_h}{C}}$Thus,the correct relation is $h = \sqrt{\frac{K_h}{C}}$.

For the reaction $HCOO^{-} + H_2O \rightleftharpoons HCOOH + OH^{-}$,which of the following relations is correct?

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