Two bodies of masses 1 g and 4 g are moving | vedclass

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Question

(C) The relationship between linear momentum $P$,mass $m$,and kinetic energy $E$ is given by $P = \sqrt{2mE}$.Since the kinetic energy $E$ is the same

Vedclass · Accepted Answer

$1 : 2$

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(C) The relationship between linear momentum $P$,mass $m$,and kinetic energy $E$ is given by $P = \sqrt{2mE}$.Since the kinetic energy $E$ is the same for both bodies,we have $P \propto \sqrt{m}$.Therefore,the ratio of their momenta is $\frac{P_1}{P_2} = \sqrt{\frac{m_1}{m_2}}$.Given $m_1 = 1 \ g$ and $m_2 = 4 \ g$,we substitute these values:$\frac{P_1}{P_2} = \sqrt{\frac{1}{4}} = \frac{1}{2}$.Thus,the ratio of their linear momenta is $1 : 2$.

Two bodies of masses $1 \ g$ and $4 \ g$ are moving with the same kinetic energy. What is the ratio of their linear momenta?

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