(B) Let $x$ be the maximum extension in the spring. At the point of maximum extension,the velocity of the block is zero.Applying the principle of cons

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(B) Let $x$ be the maximum extension in the spring. At the point of maximum extension,the velocity of the block is zero.Applying the principle of conservation of mechanical energy,the loss in gravitational potential energy of the block is equal to the gain in elastic potential energy of the spring.Loss in gravitational potential energy = $Mgx$Gain in elastic potential energy = $\frac{1}{2} k x^2$Equating the two: $Mgx = \frac{1}{2} k x^2$Solving for $x$ (where $x \neq 0$): $x = \frac{2Mg}{k}$

Class 11 Physics Work, Energy, Power and Collision Work Done by Spring and Potential Energy of Spring

Difficult

An ideal spring with spring constant $k$ is suspended from the ceiling,and a block of mass $M$ is attached to its lower end. Initially,the spring is unstretched and the block is released from rest. What will be the maximum extension in the spring?

A
$4 Mg/k$
B
$2 Mg/k$
C
$Mg/k$
D
$Mg/2k$

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Class 11 Questions

Class 11

Physics Questions

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Work, Energy, Power and Collision

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Work Done by Spring and Potential Energy of Spring

$A$ mechanical system consists of two springs with stiffness coefficients $k_1$ and $k_2$ connected in series. The minimum work to be performed on the system to stretch it by a total displacement $\Delta$ is

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$A$ spring of force constant $k$ is cut into two parts at one-third of its length. When both parts are stretched by the same amount,the work done in the two parts will be:

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If the potential energy of a spring is $V$ on stretching it by $2 \, cm$,then its potential energy when it is stretched by $10 \, cm$ will be

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The potential energy of a weightless spring compressed by a distance $a$ is proportional to

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$A$ block of mass $100 \ g$ moving at a speed of $2 \ m \ s^{-1}$ compresses a spring through a distance $2 \ cm$ before its speed is halved. Find the spring constant of the spring. (in $N \ m^{-1}$)

MediumTS EAMCET 2020

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An ideal spring with spring constant $k$ is suspended from the ceiling,and a block of mass $M$ is attached to its lower end. Initially,the spring is unstretched and the block is released from rest. What will be the maximum extension in the spring?

Similar Questions

$A$ mechanical system consists of two springs with stiffness coefficients $k_1$ and $k_2$ connected in series. The minimum work to be performed on the system to stretch it by a total displacement $\Delta$ is

$A$ spring of force constant $k$ is cut into two parts at one-third of its length. When both parts are stretched by the same amount,the work done in the two parts will be:

If the potential energy of a spring is $V$ on stretching it by $2 \, cm$,then its potential energy when it is stretched by $10 \, cm$ will be

The potential energy of a weightless spring compressed by a distance $a$ is proportional to

$A$ block of mass $100 \ g$ moving at a speed of $2 \ m \ s^{-1}$ compresses a spring through a distance $2 \ cm$ before its speed is halved. Find the spring constant of the spring. (in $N \ m^{-1}$)

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