$A$ block of weight $W$ moving with velocity $v$ on a frictionless horizontal surface hits a spring of force constant $k$. The maximum compression in the spring will be at a distance of .........

  • A
    $v\sqrt{\frac{W}{k}}$
  • B
    $v\sqrt{\frac{k}{W}}$
  • C
    $v\sqrt{\frac{W}{kg}}$
  • D
    $v\sqrt{\frac{kg}{W}}$

Explore More

Similar Questions

Two springs of spring constants $K$ and $2K$ are stretched by the same force. If $W_{1}$ and $W_{2}$ are the energies stored in them respectively,then:

$A$ spring with a force constant of $100 \ N/m$ is stretched by $5 \ cm$. Calculate the work done. (in $J$)

$A$ block of mass $M$ moving on a frictionless horizontal surface collides with a spring of spring constant $K$, as shown in the figure. If the spring compresses by a length $L$, then the maximum momentum of the block is:

An ideal spring with spring constant $k$ is suspended from the ceiling,and a block of mass $M$ is attached to its lower end. Initially,the spring is unstretched and the block is released from rest. What will be the maximum extension in the spring?

Difficult
View Solution

Does the energy stored in a spring change when it is stretched or compressed?

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo