A Carnot engine absorbs 3 times 10^{6} text{ | vedclass

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(B) The temperatures are $T_{1} = 627 + 273 = 900 	ext{ K}$ and $T_{2} = 27 + 273 = 300 	ext{ K}$.Efficiency $\eta = 1 - \frac{T_{2}}{T_{1}} = 1 - \

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$8.4 	imes 10^{6} 	ext{ J}$

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(B) The temperatures are $T_{1} = 627 + 273 = 900 	ext{ K}$ and $T_{2} = 27 + 273 = 300 	ext{ K}$.Efficiency $\eta = 1 - \frac{T_{2}}{T_{1}} = 1 - \frac{300}{900} = 1 - \frac{1}{3} = \frac{2}{3}$.Heat absorbed $Q_{1} = 3 	imes 10^{6} 	ext{ cal} = 3 	imes 10^{6} 	imes 4.2 	ext{ J} = 12.6 	imes 10^{6} 	ext{ J}$.Work done $W = \eta 	imes Q_{1} = \frac{2}{3} 	imes 12.6 	imes 10^{6} 	ext{ J} = 8.4 	imes 10^{6} 	ext{ J}$.

$A$ Carnot engine absorbs $3 \times 10^{6} \text{ cal}$ of heat from a reservoir at $627^{\circ}C$ and rejects it at $27^{\circ}C$. The work done by the engine is:

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