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(B) The work done in a cyclic process is equal to the area enclosed by the $P-V$ loop.Since the cycle $PQRSP$ is traversed in an anti-clockwise direct

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$-20$

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(B) The work done in a cyclic process is equal to the area enclosed by the $P-V$ loop.Since the cycle $PQRSP$ is traversed in an anti-clockwise direction, the work done by the system is negative.Area $= 	ext{length} 	imes 	ext{width} = (V_Q - V_P) 	imes (P_S - P_P)$$V_Q - V_P = (300 - 100) 	ext{ cc} = 200 	ext{ cc} = 200 	imes 10^{-6} 	ext{ m}^3$$P_S - P_P = (200 - 100) 	ext{ kPa} = 100 	ext{ kPa} = 100 	imes 10^3 	ext{ Pa}$Work done $W = - (	ext{Area}) = - (200 	imes 10^{-6} 	ext{ m}^3) 	imes (100 	imes 10^3 	ext{ Pa})$$W = - (200 	imes 100 	imes 10^{-3}) 	ext{ J} = -20 	ext{ J}$.

$A$ thermodynamic system undergoes a cyclic process $PQRSP$. The total work done by the system is..... $J$.

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