The efficiency of a Carnot engine operating b | vedclass

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(A) The efficiency $\eta$ of a Carnot engine is given by the formula: $\eta = 1 - \frac{T_2}{T_1}$, where $T_1$ is the source temperature and $T_2$ is

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$50$

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(A) The efficiency $\eta$ of a Carnot engine is given by the formula: $\eta = 1 - \frac{T_2}{T_1}$, where $T_1$ is the source temperature and $T_2$ is the sink temperature in Kelvin.Convert temperatures from Celsius to Kelvin: $T_1 = 27 + 273 = 300 \, K$ and $T_2 = -123 + 273 = 150 \, K$.Substitute the values into the formula: $\eta = 1 - \frac{150}{300}$.Simplify the expression: $\eta = 1 - 0.5 = 0.5$.Convert to percentage: $\eta = 0.5 	imes 100 = 50\%$.

The efficiency of a Carnot engine operating between temperatures $27^{\circ}C$ and $-123^{\circ}C$ is .... $\%$?

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