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(B) The frequency deviation $\Delta f$ is related to the channel spacing $(CS)$ by the formula $\Delta f = \frac{CS}{2}$.Given the carrier frequency s

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$10$

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(B) The frequency deviation $\Delta f$ is related to the channel spacing $(CS)$ by the formula $\Delta f = \frac{CS}{2}$.Given the carrier frequency spacing (channel spacing) $CS = 200 	ext{ kHz}$ and the modulating frequency $f_m = 10 	ext{ kHz}$.First,calculate the frequency deviation: $\Delta f = \frac{200 	ext{ kHz}}{2} = 100 	ext{ kHz}$.The modulation index $m_f$ is defined as the ratio of frequency deviation to the modulating frequency: $m_f = \frac{\Delta f}{f_m}$.Substituting the values: $m_f = \frac{100 	ext{ kHz}}{10 	ext{ kHz}} = 10$.

For an $FM$ carrier with a carrier frequency of $200 \text{ kHz}$ and a modulating frequency of $10 \text{ kHz}$,the modulation index is...

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