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Question

(B) The velocity of an electromagnetic wave in a medium is given by $v = \frac{c}{\sqrt{\mu_r \epsilon_r}}$.Assuming the medium is non-magnetic,$\mu_r

Vedclass · Accepted Answer

$1.44$

Vedclass · Answer

(B) The velocity of an electromagnetic wave in a medium is given by $v = \frac{c}{\sqrt{\mu_r \epsilon_r}}$.Assuming the medium is non-magnetic,$\mu_r \approx 1$.Thus,$v = \frac{c}{\sqrt{\epsilon_r}}$,where $\epsilon_r$ is the dielectric constant $(K)$.Rearranging for $K$,we get $\sqrt{K} = \frac{c}{v}$,so $K = \left(\frac{c}{v}ight)^2$.Given $c = 3 	imes 10^{8} \ m/s$ and $v = 2.5 	imes 10^{8} \ m/s$.$K = \left(\frac{3 	imes 10^{8}}{2.5 	imes 10^{8}}ight)^2 = \left(\frac{3}{2.5}ight)^2 = (1.2)^2 = 1.44$.

The velocity of an electromagnetic wave in a medium is $2.5 \times 10^{8} \ m/s$. What is the dielectric constant of the medium?

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