A solution of a solute in benzene has a molal | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Molality $(X)$ is defined as the number of moles of solute per $1000 \ g$ of solvent. Given,mass of solvent (benzene,$C_6H_6$) = $1000 \ g$. Molar

Vedclass · Accepted Answer

$3.2$

Vedclass · Answer

(B) Molality $(X)$ is defined as the number of moles of solute per $1000 \ g$ of solvent. Given,mass of solvent (benzene,$C_6H_6$) = $1000 \ g$. Molar mass of benzene = $78 \ g/mol$. Moles of benzene = $\frac{1000}{78} \approx 12.82 \ mol$. Mole fraction of solute $(x_{solute})$ = $\frac{n_{solute}}{n_{solute} + n_{solvent}} = 0.2$. Let $n_{solute} = X$. $\frac{X}{X + 12.82} = 0.2$. $X = 0.2X + 2.564$. $0.8X = 2.564$. $X = \frac{2.564}{0.8} = 3.205 \approx 3.2$.

$A$ solution of a solute in benzene has a molality of $X \ m$. If the mole fraction of the solute is $0.2$,what is the value of $X$?

Similar Questions

Which of the following concentration terms depends on temperature?

If $5.85 \ g$ of $NaCl$ (molecular weight $58.5$) is dissolved in water and the solution is made up to $0.5 \ L$,the molarity of the solution will be (in $M$)

The mole fraction of a solute in a $100$ molal aqueous solution is $.......... \times 10^{-2}$ (Round off to the nearest integer). [Given: Atomic masses: $H = 1.0 \ u$,$O = 16.0 \ u$]

If equal moles of water and urea are taken in a flask,what is the percentage by weight of urea?

What volume of water is to be added to $50 \, mL$ of $4 \, N$ $NaOH$ solution to obtain a $1 \, N$ solution? $(... \, mL)$

Vedclass Test Series

Exam Paper Generator

Online Exam Module