$A$ sphere rolls without slipping on a fixed horizontal surface. In the figure,$A$ is the point of contact,$B$ is the center,and $C$ is the topmost point. Then...

  • A
    $|\vec{V}_C - \vec{V}_A| = 2 |\vec{V}_B - \vec{V}_C|$
  • B
    $\vec{V}_C - \vec{V}_B = 2\vec{V}_B + \vec{V}_A$
  • C
    $|\vec{V}_A - \vec{V}_A| = 2 |\vec{V}_B - \vec{V}_C|$
  • D
    $|\vec{V}_C - \vec{V}_A| = 4 |\vec{V}_B|$

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Similar Questions

$A$ sphere is rolling without slipping on a fixed horizontal plane surface. In the figure,$A$ is the point of contact,$B$ is the centre of the sphere and $C$ is its topmost point. Then,
$(A)$ $\vec{V}_C-\vec{V}_A=2(\vec{V}_B-\vec{V}_C)$
$(B)$ $\vec{V}_C-\vec{V}_B=\vec{V}_B-\vec{V}_A$
$(C)$ $|\vec{V}_C-\vec{V}_A|=2|\vec{V}_B-\vec{V}_C|$
$(D)$ $|\vec{V}_C-\vec{V}_A|=4|\vec{V}_B|$

$A$ ring and a disc roll on a horizontal surface without slipping with the same linear velocity. If both have the same mass and the total kinetic energy of the ring is $4 \ J$,then the total kinetic energy of the disc is: (in $J$)

$A$ sphere cannot roll on a ..........

$A$ disc of radius $1\,m$ and mass $4\,kg$ rolls on a horizontal plane without slipping in such a way that its centre of mass moves with a speed of $10\,cm/s$. Its rotational kinetic energy is (in $,J$)

$A$ circular disc rolls on a horizontal floor without slipping and the centre of the disc moves with a uniform velocity $v$. Which of the following values can the velocity of a point on the rim of the disc have?

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