Two spheres A and B,each of mass 5 kg,are at | vedclass

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(D) Let the mass of each sphere be $m = 5 \ kg$ and the length of the rod be $L = 1 \ m$.Case $1$: Axis passing through $A$ and perpendicular to the r

Vedclass · Accepted Answer

$2 : 1$

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(D) Let the mass of each sphere be $m = 5 \ kg$ and the length of the rod be $L = 1 \ m$.Case $1$: Axis passing through $A$ and perpendicular to the rod.The moment of inertia $I_1$ is given by:$I_1 = m_A \cdot (0)^2 + m_B \cdot (L)^2 = 0 + m \cdot (1)^2 = m$Case $2$: Axis passing through the center of the rod and perpendicular to it.The moment of inertia $I_2$ is given by:$I_2 = m_A \cdot (L/2)^2 + m_B \cdot (L/2)^2 = m \cdot (0.5)^2 + m \cdot (0.5)^2 = 0.25m + 0.25m = 0.5m = m/2$Ratio of moments of inertia:$I_1 / I_2 = m / (m/2) = 2 / 1$Thus,the ratio is $2 : 1$.

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