Difficult
$A$ uniform rod of mass $8m$ and length $6a$ is placed on a horizontal table. Two point masses $m$ and $2m$ are moving with speeds $2v$ and $v$ respectively,as shown in the figure. They strike the rod and stick to it after the collision. Find the angular velocity of the rod about an axis passing through its center of mass.
- A$\frac{v}{a}$
- B$\frac{v}{5a}$
- C$\frac{2v}{5a}$
- D$\frac{5v}{3a}$
Explore More
Similar Questions
$A$ particle of mass $= 5 \text{ units}$ is moving with a uniform speed $V = 3 \sqrt{2} \text{ units}$ in the $XOY$ plane along the line $Y = X + 4$. The magnitude of the angular momentum of the particle about the origin is ...... $\text{units}$.
Difficult
View SolutionDefine angular momentum.
Easy
View SolutionIn orbital motion,the angular momentum vector is directed:
$A$ particle of mass $0.01 \ kg$ has a position vector $\vec{r} = (10\hat{i} + 6\hat{j}) \ m$ and moves with a velocity $\vec{v} = 5\hat{i} \ m/s$. Calculate its angular momentum about the origin in $\hat{k} \ J \cdot s$.
Easy
View Solution$A$ particle moves along a circular path with decreasing speed. Hence,
Vedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo