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(A) The total pressure $P$ in the vessel is given by the ideal gas equation $PV = n_{total}RT$,where $n_{total} = n_{O_2} + n_{N_2} + n_{CO_2}$.$1$. C

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$5 	imes 10^5 \ Pa$

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(A) The total pressure $P$ in the vessel is given by the ideal gas equation $PV = n_{total}RT$,where $n_{total} = n_{O_2} + n_{N_2} + n_{CO_2}$.$1$. Calculate the number of moles for each gas:$n_{O_2} = \frac{6 \ g}{32 \ g/mol} = 0.1875 \ mol$$n_{N_2} = \frac{8 \ g}{28 \ g/mol} \approx 0.2857 \ mol$$n_{CO_2} = \frac{5 \ g}{44 \ g/mol} \approx 0.1136 \ mol$$2$. Total moles $n_{total} = 0.1875 + 0.2857 + 0.1136 \approx 0.5868 \ mol$.$3$. Convert volume and temperature to $SI$ units:$V = 3 \ L = 3 	imes 10^{-3} \ m^3$$T = 27^{\circ}C = 300 \ K$$4$. Calculate total pressure:$P = \frac{n_{total}RT}{V} = \frac{0.5868 	imes 8.31 	imes 300}{3 	imes 10^{-3}} \approx 4.87 	imes 10^5 \ Pa \approx 5 	imes 10^5 \ Pa$.

$A$ vessel has a capacity of $3 \ L$. If it contains a mixture of $6 \ g$ of $O_2$,$8 \ g$ of $N_2$,and $5 \ g$ of $CO_2$,what will be the pressure of the vessel at a temperature of $27^{\circ}C$? (Given $R = 8.31 \ J/mol \cdot K$)

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