If the rms speed of a gas is v_{rms} = 1840 | vedclass

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(C) The formula for the $rms$ speed of a gas is given by $v_{rms} = \sqrt{\frac{3P}{\rho}}$.Rearranging the formula to solve for pressure $P$,we get $

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$1.01 	imes 10^5 \ N/m^2$

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(C) The formula for the $rms$ speed of a gas is given by $v_{rms} = \sqrt{\frac{3P}{ho}}$.Rearranging the formula to solve for pressure $P$,we get $P = \frac{1}{3} ho v_{rms}^2$.Given values are $v_{rms} = 1840 \ m/s$ and $ho = 8.99 	imes 10^{-2} \ kg/m^3$.Substituting these values into the equation:$P = \frac{1}{3} 	imes (8.99 	imes 10^{-2}) 	imes (1840)^2$$P = \frac{1}{3} 	imes (8.99 	imes 10^{-2}) 	imes 3385600$$P = \frac{1}{3} 	imes 304365.44$$P \approx 101455.15 \ N/m^2$$P \approx 1.01 	imes 10^5 \ N/m^2$.Thus,the correct option is $C$.

If the $rms$ speed of a gas is $v_{rms} = 1840 \ m/s$ and its density is $\rho = 8.99 \times 10^{-2} \ kg/m^3$,then the pressure of the gas will be .........

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