Oxygen gas is filled in a container of volume | vedclass

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Question

(B) Given: Pressure $P = 2.5 	imes 10^5 \, N \, m^{-2}$Volume $V = 20 \, L = 20 	imes 10^{-3} \, m^3$Temperature $T = 27 \, ^\circ C = 27 + 273 = 30

Vedclass · Accepted Answer

$64 \, g$

Vedclass · Answer

(B) Given: Pressure $P = 2.5 	imes 10^5 \, N \, m^{-2}$Volume $V = 20 \, L = 20 	imes 10^{-3} \, m^3$Temperature $T = 27 \, ^\circ C = 27 + 273 = 300 \, K$Molar mass $M = 32 \, g \, mol^{-1} = 32 	imes 10^{-3} \, kg \, mol^{-1}$Gas constant $R = 8.31 \, J \, mol^{-1} K^{-1}$Using the ideal gas equation $PV = \mu RT$,where $\mu = \frac{m}{M}$:$PV = \frac{m}{M} RT$$m = \frac{PVM}{RT}$Substituting the values:$m = \frac{(2.5 	imes 10^5) 	imes (20 	imes 10^{-3}) 	imes (32 	imes 10^{-3})}{8.31 	imes 300}$$m = \frac{2.5 	imes 20 	imes 32 	imes 10^{-1}}{2493}$$m = \frac{1600 	imes 10^{-1}}{2493} \approx 0.06418 \, kg$Rounding to the nearest significant value provided in the options,$m = 0.064 \, kg = 64 \, g$.

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