A nucleus of mass M + Delta m is at rest and | vedclass

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(D) In a nuclear decay process,energy is released because the system moves towards a more stable state.Stability is directly related to the binding en

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$E_2 > E_1$

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(D) In a nuclear decay process,energy is released because the system moves towards a more stable state.Stability is directly related to the binding energy per nucleon.$A$ nucleus with higher binding energy per nucleon is more stable.Since the parent nucleus decays into daughter nuclei,the daughter nuclei must be more stable than the parent nucleus.Therefore,the binding energy per nucleon of the daughter nuclei $(E_2)$ must be greater than the binding energy per nucleon of the parent nucleus $(E_1)$.Thus,$E_2 > E_1$.

$A$ nucleus of mass $M + \Delta m$ is at rest and decays into two daughter nuclei of equal mass. If $C$ is the speed of light,and $E_1$ is the binding energy per nucleon for the parent nucleus and $E_2$ is that for the daughter nuclei,then:

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