In Rutherford's alpha-particle scattering exp | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Rutherford's $\alpha$-particle scattering experiment involved bombarding a thin gold foil with high-energy $\alpha$-particles. Most of the $\alpha

Vedclass · Accepted Answer

Nucleus

Vedclass · Answer

(A) Rutherford's $\alpha$-particle scattering experiment involved bombarding a thin gold foil with high-energy $\alpha$-particles. Most of the $\alpha$-particles passed straight through the foil,but a small fraction were deflected by large angles,and some even bounced back. This observation led Rutherford to conclude that the positive charge and most of the mass of the atom are concentrated in a very small,dense central region,which he named the 'nucleus'. Therefore,the experiment led to the discovery of the atomic nucleus.

In Rutherford's $\alpha$-particle scattering experiment,which of the following was discovered?

Similar Questions

What is the dimension of an atom?

Are atoms divisible or indivisible? Explain.

What was the thickness of the gold foil used in the Geiger-Marsden scattering experiment?

The distance of closest approach of an alpha particle to a nucleus when the alpha particle moves towards the nucleus with linear momentum $P$ is $d$. What is the distance of closest approach of the alpha particle to the nucleus if the linear momentum of the alpha particle is $1.5 P$?

In the alpha particle scattering experiment,if $v$ is the initial velocity of the particle,then the distance of closest approach is $d$. If the velocity is doubled,then the distance of closest approach changes to:

Vedclass Test Series

Exam Paper Generator

Online Exam Module