The energy required to excite an electron fro | vedclass

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(A) The energy of an electron in the $n^{th}$ orbit of a hydrogen-like ion is given by the formula: $E_n = -13.6 	imes \frac{Z^2}{n^2} \ eV$. For $Li

Vedclass · Accepted Answer

$108.8$

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(A) The energy of an electron in the $n^{th}$ orbit of a hydrogen-like ion is given by the formula: $E_n = -13.6 	imes \frac{Z^2}{n^2} \ eV$. For $Li^{++}$,the atomic number $Z = 3$. The energy in the $1^{st}$ orbit $(n_1 = 1)$ is: $E_1 = -13.6 	imes \frac{3^2}{1^2} = -13.6 	imes 9 = -122.4 \ eV$. The energy in the $3^{rd}$ orbit $(n_2 = 3)$ is: $E_3 = -13.6 	imes \frac{3^2}{3^2} = -13.6 	imes 1 = -13.6 \ eV$. The energy required for excitation is: $\Delta E = E_3 - E_1 = -13.6 - (-122.4) = 108.8 \ eV$.

The energy required to excite an electron from the $1^{st}$ to the $3^{rd}$ Bohr orbit in $Li^{++}$ is ...... $eV$.

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