The binding energy per nucleon for a deuteron | vedclass

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(A) The reaction is $_1H^2 + _1H^2 \rightarrow {_2}{He}^4 + Q$.The total number of nucleons in the reactants is $2 + 2 = 4$.The binding energy per nuc

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$4(x_2 - x_1)$

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(A) The reaction is $_1H^2 + _1H^2 ightarrow {_2}{He}^4 + Q$.The total number of nucleons in the reactants is $2 + 2 = 4$.The binding energy per nucleon for the deuteron is $x_1$, so the total binding energy of the reactants is $4x_1$.The total number of nucleons in the product is $4$.The binding energy per nucleon for the $\alpha$-particle is $x_2$, so the total binding energy of the product is $4x_2$.The energy released $Q$ is given by the difference in total binding energies: $Q = (	ext{Total Binding Energy of Products}) - (	ext{Total Binding Energy of Reactants})$.Therefore, $Q = 4x_2 - 4x_1 = 4(x_2 - x_1)$.

The binding energy per nucleon for a deuteron and an $\alpha$-particle are $x_1$ and $x_2$ respectively. The energy $Q$ released in the following reaction is:
$_1H^2 + _1H^2 \rightarrow {_2}{He}^4 + Q$

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The binding energy per nucleon for a deuteron and an $\alpha$-particle are $x_1$ and $x_2$ respectively. The energy $Q$ released in the following reaction is:$_1H^2 + _1H^2 \rightarrow {_2}{He}^4 + Q$