The mass of the oxygen isotope $_8O^{17}$ is $M_0$. If $M_p$ and $M_n$ are the masses of a proton and a neutron respectively,the nuclear binding energy of the isotope is ......

  • A
    $(17 M_n - M_0) c^2$
  • B
    $(8 M_p - M_0) c^2$
  • C
    $(8 M_p + 9 M_n - M_0) c^2$
  • D
    $M_0 c^2$

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The binding energy per nucleon for $_8O^{16}$ and $_8O^{17}$ are $7.97 \, MeV$ and $7.75 \, MeV$ respectively. The energy required to remove a neutron from $_8O^{17}$ is (in $MeV$):

$M_n$ and $M_p$ represent the mass of a neutron and a proton, respectively. If an element having atomic mass $M$ has $N$ neutrons and $Z$ protons, then the correct relation is:

The binding energy per nucleon of $^{209}_{83}Bi$ is . . . . . . MeV. [Take $m(^{209}_{83}Bi) = 208.980388 \text{ u}$, $m_p = 1.007825 \text{ u}$, $m_n = 1.008665 \text{ u}$, $1 \text{ u} = 931 \text{ MeV}/c^2$]

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