Find the ratio of the energy of an X-ray phot | vedclass

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(B) The energy $E$ of a photon is given by the formula $E = \frac{hc}{\lambda}$.Since $h$ (Planck's constant) and $c$ (speed of light) are constants,t

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$5000:1$

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(B) The energy $E$ of a photon is given by the formula $E = \frac{hc}{\lambda}$.Since $h$ (Planck's constant) and $c$ (speed of light) are constants,the energy is inversely proportional to the wavelength: $E \propto \frac{1}{\lambda}$.Let $E_1$ be the energy of the $X$-ray photon with wavelength $\lambda_1 = 1 \mathring A$.Let $E_2$ be the energy of the visible light photon with wavelength $\lambda_2 = 5000 \mathring A$.The ratio of the energies is given by $\frac{E_1}{E_2} = \frac{\lambda_2}{\lambda_1}$.Substituting the given values: $\frac{E_1}{E_2} = \frac{5000 \mathring A}{1 \mathring A} = 5000$.Therefore,the ratio is $5000:1$.

Find the ratio of the energy of an $X$-ray photon with a wavelength of $1 \mathring A$ to the energy of a visible light photon with a wavelength of $5000 \mathring A$.

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