If the binding energy per nucleon for $\,_3^7\,Li\,\,$ and $\,_2^4\,\,He$ are $5.60 \,MeV$ and $7.06 \,MeV$ respectively, then the energy of the proton in the reaction $p\,\, + \,\,_3^7\,\,Li\,\, \to \,\,2\,_2^4\,\,He$ must be .......... $MeV$.

The binding energy per nucleon for $_8O^{16}$ and $_8O^{17}$ are $7.97 \, MeV$ and $7.75 \, MeV$ respectively. The energy required to remove a neutron from $_8O^{17}$ is (in $MeV$):

The plot of binding energy per nucleon against the mass number for stable nuclei is shown in the figure. Which curve is correct?

Given below are two statements:
Statement $I$: For all elements, greater the mass of the nucleus, greater is the binding energy per nucleon.
Statement $II$: For all elements, nuclei with less binding energy per nucleon transform to nuclei with greater binding energy per nucleon.
In the light of the above statements, choose the correct answer from the options given below:

From the given data,the amount of energy required to break the nucleus of aluminium ${ }_{13}^{27} {Al}$ is $x \times 10^{-3} {J}$.
Mass of neutron $= 1.00866 \, {u}$
Mass of proton $= 1.00726 \, {u}$
Mass of aluminium nucleus $= 26.98154 \, {u}$
(Assume $1 \, {u}$ corresponds to $1 \, {J}$ of energy for the purpose of this calculation)
(Round off to the nearest integer)

The radionuclide $^{11}_{6}C$ decays by $\beta^+$ emission. Given that $m(^{11}_{6}C) = 11.011434 \ u$,$m(^{11}_{5}B) = 11.009305 \ u$,$m_e = 0.000548 \ u$,and $1 \ u = 931.5 \ MeV/c^2$. The $Q$-value of this decay process is: