For an X-ray tube operating at 40 , kV, which | vedclass

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(A) The minimum wavelength (cut-off wavelength) of $X$-rays produced is given by the formula: $\lambda_{min} = \frac{hc}{eV} = \frac{12400}{V(\in \, v

Vedclass · Accepted Answer

$0.25$

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(A) The minimum wavelength (cut-off wavelength) of $X$-rays produced is given by the formula: $\lambda_{min} = \frac{hc}{eV} = \frac{12400}{V(\in \, volts)} \, \mathring{A}$.Given the potential difference $V = 40 \, kV = 40,000 \, V$.Substituting the values: $\lambda_{min} = \frac{12400}{40000} \, \mathring{A} = 0.31 \, \mathring{A}$.Any wavelength shorter than the minimum wavelength $\lambda_{min}$ is not possible.Since $0.25 \, \mathring{A} < 0.31 \, \mathring{A}$, the wavelength $0.25 \, \mathring{A}$ is not possible.

For an $X$-ray tube operating at $40 \, kV$, which of the following wavelengths is $NOT$ possible?

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