For the production of X-rays of wavelength 0. | vedclass

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(C) The minimum wavelength of $X$-rays produced is given by the formula: $\lambda_{\min} = \frac{hc}{eV}$.Substituting the values of $h$,$c$,and $e$,w

Vedclass · Accepted Answer

$124$

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(C) The minimum wavelength of $X$-rays produced is given by the formula: $\lambda_{\min} = \frac{hc}{eV}$.Substituting the values of $h$,$c$,and $e$,we get the relation: $\lambda_{\min} (	ext{in } \mathring{A}) = \frac{12400}{V (	ext{in volts})}$.Given $\lambda_{\min} = 0.1 \mathring{A}$.Therefore,$0.1 = \frac{12400}{V}$.$V = \frac{12400}{0.1} = 124000 	ext{ V}$.Converting to kilovolts $(kV)$,$V = 124 	ext{ kV}$.

For the production of $X$-rays of wavelength $0.1 \mathring{A}$,the minimum potential difference required will be.....$kV$.

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