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(D) The energy density $(u)$ of an electric field $(E)$ in a vacuum is given by the formula:$u = \frac{1}{2} \epsilon_0 E^2$Where:$u$ is the energy de

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$E^2$

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(D) The energy density $(u)$ of an electric field $(E)$ in a vacuum is given by the formula:$u = \frac{1}{2} \epsilon_0 E^2$Where:$u$ is the energy density (energy per unit volume),$\epsilon_0$ is the permittivity of free space,$E$ is the magnitude of the electric field.From the formula,it is clear that the energy density $u$ is directly proportional to the square of the electric field magnitude $(E^2)$.Therefore,the correct option is $D$.

The energy density of an electric field is proportional to which of the following?

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