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(A) The torque $\vec{	au}$ acting on an electric dipole placed in a uniform electric field is given by the cross product: $\vec{	au} = \vec{p} 	ime

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(A) The torque $\vec{	au}$ acting on an electric dipole placed in a uniform electric field is given by the cross product: $\vec{	au} = \vec{p} 	imes \vec{E}$.The magnitude of the torque is given by: $	au = pE \sin(	heta)$,where $	heta$ is the angle between the dipole moment $\vec{p}$ and the electric field $\vec{E}$.For the torque to be maximum,$\sin(	heta)$ must be maximum.The maximum value of $\sin(	heta)$ is $1$,which occurs when $	heta = 90^{\circ}$.Therefore,the torque is maximum when the angle between $\vec{p}$ and $\vec{E}$ is $90^{\circ}$.

When an electric dipole $\vec{p}$ is placed in a uniform electric field $\vec{E}$,for what angle (in degrees) between $\vec{p}$ and $\vec{E}$ will the torque be maximum?

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