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Question

(B) The potential energy $U$ of an electric dipole in an external electric field is given by the formula:$U = -\vec{P} \cdot \vec{E} = -PE \cos 	heta

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$-7 	imes 10^{-27}\,J$

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(B) The potential energy $U$ of an electric dipole in an external electric field is given by the formula:$U = -\vec{P} \cdot \vec{E} = -PE \cos 	heta$Given values:Electric field $E = 1000\,V/m = 10^3\,V/m$Dipole moment $P = 10^{-29}\,C\cdot m$Angle $	heta = 45^\circ$Substituting the values into the formula:$U = -(10^{-29}) 	imes (10^3) 	imes \cos(45^\circ)$$U = -10^{-26} 	imes \frac{1}{\sqrt{2}}$$U = -10^{-26} 	imes 0.7071$$U = -0.7071 	imes 10^{-26}\,J$$U = -7.071 	imes 10^{-27}\,J$Rounding to the nearest provided option,we get:$U \approx -7 	imes 10^{-27}\,J$

An electric field of $1000\,V/m$ is applied to an electric dipole at an angle of $45^\circ$. The value of the electric dipole moment is $10^{-29}\,C\cdot m$. What is the potential energy of the electric dipole?

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