In the common crystal structure of CsCl,Cs^+ | vedclass

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(A) Step $1$: Analyze the symmetry of the $CsCl$ crystal structure.In the $bcc$ structure of $CsCl$,the $Cl^-$ ion is located at the exact center of t

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$zero$

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(A) Step $1$: Analyze the symmetry of the $CsCl$ crystal structure.In the $bcc$ structure of $CsCl$,the $Cl^-$ ion is located at the exact center of the cube,while the eight $Cs^+$ ions are located at the eight corners of the cube.Step $2$: Calculate the net force.Due to the cubic symmetry,each $Cs^+$ ion at a corner exerts an electrostatic force on the central $Cl^-$ ion. Since the $Cl^-$ ion is at the geometric center,for every $Cs^+$ ion at one corner,there is an identical $Cs^+$ ion at the diagonally opposite corner.Step $3$: Conclusion.The forces exerted by these pairs of diagonally opposite $Cs^+$ ions on the central $Cl^-$ ion are equal in magnitude and opposite in direction. Consequently,these forces cancel each other out completely.Therefore,the net electrostatic force on the $Cl^-$ ion is $zero$.

In the common crystal structure of $CsCl$,$Cs^+$ and $Cl^-$ ions are arranged in a $bcc$ structure as shown in the figure. The net electrostatic force on the $Cl^-$ ion due to the eight $Cs^+$ ions is .......

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