$A$ negatively charged oil drop is prevented from falling under gravity by applying a vertical electric field of $100 \ V m^{-1}$. If the mass of the drop is $1.6 \times 10^{-3} \ g$,the number of electrons contained in the drop is:

  • A
    $10^{18}$
  • B
    $10^{15}$
  • C
    $10^6$
  • D
    $10^{12}$

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