(A) The energy stored in the capacitor is completely converted into heat energy in the block.The energy stored in a capacitor is given by $U = \frac{1

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(A) The energy stored in the capacitor is completely converted into heat energy in the block.The energy stored in a capacitor is given by $U = \frac{1}{2}CV^2$.The heat energy absorbed by the block is given by $Q = mS\Delta T$.Equating the two energies: $\frac{1}{2}CV^2 = mS\Delta T$.Solving for the potential difference $V$: $V^2 = \frac{2mS\Delta T}{C}$.Therefore,$V = \sqrt{\frac{2mS\Delta T}{C}}$.

Class 12 Physics Electric Potential and Capacitance Energy Stored in a Capacitor

Difficult

$A$ capacitor of capacitance $C$ is fully charged. It is discharged through a small coil of negligible resistance embedded in a thermally insulated block of mass $m$ and specific heat capacity $S$. If the temperature of the block rises by $\Delta T$,find the potential difference across the capacitor.

A
$\sqrt{\frac{2mS\Delta T}{C}}$
B
$\frac{mC\Delta T}{S}$
C
$\frac{mS\Delta T}{C}$
D
$\sqrt{\frac{2mC\Delta T}{S}}$

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Class 12 Questions

Class 12

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Chapter

Electric Potential and Capacitance

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Energy Stored in a Capacitor

Two capacitors,one of capacity $C$ and the other of capacity $\frac{C}{2}$,are connected to a $V \text{ volt}$ battery,as shown. The work done in charging fully both the capacitors is

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If the distance between the plates of a capacitor having capacity $C$ and charge $Q$ is doubled,then the work done will be:

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If the energy density in a parallel plate capacitor is given as $1.8 \times 10^{-9} \ J/m^3$,then the value of the electric field in the region between the plates is ....... $NC^{-1}$. (Given: $\epsilon_0 = 9 \times 10^{-12} \ C^2/N \cdot m^2$)

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The energy stored in a capacitor is in the form of

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Three plates $A, B, C$ each of area $50 \, cm^2$ have a separation of $3 \, mm$ between $A$ and $B$ and $3 \, mm$ between $B$ and $C$. The energy stored when the plates are fully charged is (as shown in the figure):

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Two capacitors,one of capacity $C$ and the other of capacity $\frac{C}{2}$,are connected to a $V \text{ volt}$ battery,as shown. The work done in charging fully both the capacitors is

If the distance between the plates of a capacitor having capacity $C$ and charge $Q$ is doubled,then the work done will be:

If the energy density in a parallel plate capacitor is given as $1.8 \times 10^{-9} \ J/m^3$,then the value of the electric field in the region between the plates is ....... $NC^{-1}$. (Given: $\epsilon_0 = 9 \times 10^{-12} \ C^2/N \cdot m^2$)

The energy stored in a capacitor is in the form of

Three plates $A, B, C$ each of area $50 \, cm^2$ have a separation of $3 \, mm$ between $A$ and $B$ and $3 \, mm$ between $B$ and $C$. The energy stored when the plates are fully charged is (as shown in the figure):

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