If the distance between the plates of a capacitor is halved and the area of the plates is doubled,what will be the new capacitance?

The capacity of a parallel plate capacitor depends on

What is the area of the plates of a $3\,F$ parallel plate capacitor,if the separation between the plates is $5\,mm$?

The area of each plate of a parallel plate capacitor is $100 \, cm^2$ and the distance between the plates is $1 \, mm$. It is filled with mica of dielectric constant $6$. The radius of the equivalent capacity of the sphere will be.......$m$.

$A$ parallel-plate capacitor consists of a fixed plate and a movable plate that is allowed to slide in the direction parallel to the plates. Let $x$ be the distance of overlap,as shown in the figure. The separation between the plates is fixed. Assume that the plates are electrically isolated,so that their charges $\pm Q$ are constant. Force on the movable plate is proportional to

The capacity of a parallel plate capacitor is $10\,\mu F$,when the distance between its plates is $8\,cm$. If the distance between the plates is reduced to $4\,cm$,then the capacity of this parallel plate capacitor will be.........$\mu F$.