$A$ closed surface passes through a spherical conductor as shown in the figure. If a negative charge $-Q$ is placed at point $P$,what will be the nature of the electric flux coming out of the closed surface?

The figure shows electric field lines due to a charge configuration. From this,we conclude that:

$A$ charge $q$ is located at the centre of a cube. The electric flux through any face is

An electric field,$\overrightarrow{E} = \frac{2 \hat{i} + 6 \hat{j} + 8 \hat{k}}{\sqrt{6}} \ V/m$,passes through a surface of $4 \ m^2$ area having a unit normal vector $\hat{n} = \left( \frac{2 \hat{i} + \hat{j} + \hat{k}}{\sqrt{6}} \right)$. The electric flux through that surface is:

Consider an electric field $\vec{E} = E_0 \hat{i}$,where $E_0$ is a constant. The flux through the shaded area (as shown in the figure) due to this field is

$A$ uniform electric field $E = 3 \times 10^5 \text{ NC}^{-1}$ is acting along the positive $Y$-axis. The electric flux through a rectangle of area $10 \text{ cm} \times 30 \text{ cm}$ whose plane is parallel to the $ZX$-plane is