(B) The charge $Q$ transferred is given by $Q = ne$,where $n = 6.25 \times 10^{15}$ and $e = 1.6 \times 10^{-19} \, C$.$Q = (6.25 \times 10^{15}) \tim

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(B) The charge $Q$ transferred is given by $Q = ne$,where $n = 6.25 \times 10^{15}$ and $e = 1.6 \times 10^{-19} \, C$.$Q = (6.25 \times 10^{15}) \times (1.6 \times 10^{-19}) = 10 \times 10^{-4} = 10^{-3} \, C$.The capacitance $C$ is given by $C = \frac{Q}{V}$.Given $V = 100 \, V$,we have $C = \frac{10^{-3}}{100} = 10^{-5} \, F$.To convert to $\mu F$,$C = 10^{-5} \times 10^6 \, \mu F = 10 \, \mu F$.

Class 12 Physics Electrostatic Potential and Capacitance Basic of Capacitor and type of capacitor (Spherical, Cylindrical)

Easy

Two isolated conductors are charged by transferring electrons from one to the other. If transferring $6.25 \times 10^{15}$ electrons from one conductor to the other creates a potential difference of $100 \, V$,what is the capacitance of the system in $\mu F$?

A
$15$
B
$10$
C
$5$
D
$12$

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Electrostatic Potential and Capacitance

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Basic of Capacitor and type of capacitor (Spherical, Cylindrical)

The potentials of the two plates of a capacitor are $+10\,V$ and $-10\,V$. The charge on one of the plates is $40\,C$. The capacitance of the capacitor is........$F$.

Easy

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The unit of permittivity of free space is

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The electric field between the two spheres of a charged spherical capacitor:

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$A$ spherical capacitor consists of two concentric spherical conductors. Find the capacitance of the spherical capacitor if the outer radius is $2 R$ and the inner radius is $R$.

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Four capacitors,each of $25\,\mu F$,are connected as shown in the figure. The $dc$ voltmeter reads $200\,V$. The charge on each plate of the capacitor is

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Two isolated conductors are charged by transferring electrons from one to the other. If transferring $6.25 \times 10^{15}$ electrons from one conductor to the other creates a potential difference of $100 \, V$,what is the capacitance of the system in $\mu F$?

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