(A) Since the capacitors are connected in parallel to the same battery,the potential difference $V$ across both capacitors is the same.The charge on a

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(A) Since the capacitors are connected in parallel to the same battery,the potential difference $V$ across both capacitors is the same.The charge on a capacitor is given by $q = CV$.For capacitor $C_1$ (air-filled),the capacitance is $C_1 = C_0$.For capacitor $C_2$ (dielectric-filled),the capacitance is $C_2 = KC_0$,where $K > 1$.Thus,$q_1 = C_1 V = C_0 V$ and $q_2 = C_2 V = KC_0 V$.Since $K > 1$,it follows that $KC_0 V > C_0 V$,which implies $q_2 > q_1$ or $q_1 < q_2$.

Class 12 Physics Electric Potential and Capacitance Effect of Dielectric Inside Capacitor

Easy

In the given circuit,two identical capacitors $C_1$ and $C_2$ are connected to a battery. The space between the plates of $C_1$ is filled with air,while the space between the plates of $C_2$ is filled with a dielectric material of dielectric constant $K$. Then,

A
$q_1 < q_2$
B
$q_1 > q_2$
C
$q_1 = q_2$
D
None of these

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Class 12

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Electric Potential and Capacitance

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Effect of Dielectric Inside Capacitor

An air capacitor of capacity $C = 10\,\mu F$ is connected to a constant voltage battery of $12\,V$. Now,the space between the plates is filled with a liquid of dielectric constant $K = 5$. The charge that flows from the battery to the capacitor is......$\mu C$.

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$A$ parallel plate capacitor has plates of area $A$ and a separation distance of $100 \ mm$. It contains two dielectric layers: one with a dielectric constant of $10$ and a thickness of $6 \ mm$,and another with a dielectric constant of $5$ and a thickness of $4 \ mm$. Find the capacitance of the capacitor.

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Half of the space between the plates of a parallel plate capacitor is filled with a medium of dielectric constant $K$ parallel to the plates. If the initial capacitance is $C$,then the new capacitance will be:

Difficult

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$A$ parallel plate capacitor has charge $5 \times 10^{-6} \ C$. $A$ dielectric slab is inserted between the plates and almost fills the space between the plates. If the induced charge on one face of the slab is $4 \times 10^{-6} \ C$, then the dielectric constant of the slab is . . . . . . .

DifficultJEE MAIN 2025

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The capacity of an air condenser is $2.0 \, \mu F$. If a medium is placed between its plates,the capacity becomes $12 \, \mu F$. The dielectric constant of the medium will be:

Easy

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In the given circuit,two identical capacitors $C_1$ and $C_2$ are connected to a battery. The space between the plates of $C_1$ is filled with air,while the space between the plates of $C_2$ is filled with a dielectric material of dielectric constant $K$. Then,

Similar Questions

An air capacitor of capacity $C = 10\,\mu F$ is connected to a constant voltage battery of $12\,V$. Now,the space between the plates is filled with a liquid of dielectric constant $K = 5$. The charge that flows from the battery to the capacitor is......$\mu C$.

Half of the space between the plates of a parallel plate capacitor is filled with a medium of dielectric constant $K$ parallel to the plates. If the initial capacitance is $C$,then the new capacitance will be:

$A$ parallel plate capacitor has charge $5 \times 10^{-6} \ C$. $A$ dielectric slab is inserted between the plates and almost fills the space between the plates. If the induced charge on one face of the slab is $4 \times 10^{-6} \ C$, then the dielectric constant of the slab is . . . . . . .

The capacity of an air condenser is $2.0 \, \mu F$. If a medium is placed between its plates,the capacity becomes $12 \, \mu F$. The dielectric constant of the medium will be:

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