A radioactive substance in the form of a meta | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The capacitance of a spherical conductor is given by $C = 4\pi \varepsilon_0 R$.Given diameter $d = 10^{-3} \ m$,so radius $R = 0.5 	imes 10^{-3}

Vedclass · Accepted Answer

$6.95$

Vedclass · Answer

(C) The capacitance of a spherical conductor is given by $C = 4\pi \varepsilon_0 R$.Given diameter $d = 10^{-3} \ m$,so radius $R = 0.5 	imes 10^{-3} \ m$.$C = \frac{0.5 	imes 10^{-3}}{9 	imes 10^9} = \frac{1}{18} 	imes 10^{-12} \ F$.The rate of charge emission from the surface is $I = 0.80 	imes (6.25 	imes 10^{10}) 	imes (1.6 	imes 10^{-19}) \ C/s$.$I = 0.80 	imes 10 	imes 10^{-9} = 8 	imes 10^{-9} \ C/s$.Using $q = CV$,where $q = I 	imes t$:$(8 	imes 10^{-9}) 	imes t = (\frac{1}{18} 	imes 10^{-12}) 	imes 1.0$.$t = \frac{10^{-12}}{8 	imes 10^{-9} 	imes 18} = \frac{10^{-3}}{144} \approx 6.944 	imes 10^{-6} \ s = 6.944 \ \mu s$.Rounding to the nearest option,$t \approx 6.95 \ \mu s$.

Similar Questions

The diagram shows four capacitors with capacitances and breakdown voltages as mentioned. What should be the maximum value of the external emf source such that no capacitor breaks down? (in $kV$)

Find the potential difference between points $A$ and $F$,and $F$ and $B$.

Plates $A$ and $B$ constitute an isolated,charged parallel-plate capacitor. The inner surfaces ($I$ and $IV$) of $A$ and $B$ have charges $+Q$ and $-Q$ respectively. $A$ third plate $C$ with charge $+Q$ is now introduced midway between $A$ and $B$. Which of the following statements is not correct?

Five identical capacitors, each of capacitance $20 \mu F$, are connected to a battery of $150 V$ in the combination shown in the diagram. What is the total amount of charge stored?

Vedclass Test Series

Exam Paper Generator

Online Exam Module