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(C) The circuit consists of three $NAND$ gates and one $NOR$ gate. Let the inputs be $A$ and $B$. The first two $NAND$ gates act as $NOT$ gates becaus

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$NOR$ gate

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(C) The circuit consists of three $NAND$ gates and one $NOR$ gate. Let the inputs be $A$ and $B$. The first two $NAND$ gates act as $NOT$ gates because their inputs are shorted. So,the outputs of the first two gates are $\bar{A}$ and $\bar{B}$. These are fed into the third $NAND$ gate. The output of the third $NAND$ gate is $Y' = \overline{\bar{A} \cdot \bar{B}} = A + B$. This $Y'$ is then passed through a $NOR$ gate. The final output is $Y = \overline{Y' + 0} = \overline{A + B}$. This is the Boolean expression for a $NOR$ gate.

Which gate is formed by the combination of gates shown below?

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