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(B) The circuit consists of two $NAND$ gates used as $NOT$ gates (since their inputs are shorted) followed by a $NAND$ gate.Let the inputs be $A$ and

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$OR$ gate

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(B) The circuit consists of two $NAND$ gates used as $NOT$ gates (since their inputs are shorted) followed by a $NAND$ gate.Let the inputs be $A$ and $B$.The output of the first $NAND$ gate (acting as $NOT$) is $\overline{A}$.The output of the second $NAND$ gate (acting as $NOT$) is $\overline{B}$.These are fed into the final $NAND$ gate.The output $X = \overline{(\overline{A} \cdot \overline{B})}$.Using De Morgan's Law,$X = \overline{\overline{A}} + \overline{\overline{B}} = A + B$.Thus,the combination acts as an $OR$ gate.

The given circuit shows a combination of logic gates. Identify the equivalent gate.

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