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(B) The relationship between emitter current $(I_E)$,collector current $(I_C)$,and base current $(I_B)$ is given by $I_E = I_C + I_B$.Therefore,$I_C =

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$\frac{24}{25}$

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(B) The relationship between emitter current $(I_E)$,collector current $(I_C)$,and base current $(I_B)$ is given by $I_E = I_C + I_B$.Therefore,$I_C = I_E - I_B$.Given $I_E = 25 \, mA$ and $I_B = 1 \, mA$,we have $I_C = 25 \, mA - 1 \, mA = 24 \, mA$.The ratio of collector current to emitter current is $\alpha = \frac{I_C}{I_E}$.Substituting the values,$\alpha = \frac{24 \, mA}{25 \, mA} = \frac{24}{25}$.

For a transistor,if the emitter current $I_E = 25 \, mA$ and the base current $I_B = 1 \, mA$,what is the ratio of the collector current $I_C$ to the emitter current $I_E$?

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