In an $NPN$ transistor circuit,the collector current is $10 \ mA$. If $95\%$ of the electrons emitted reach the collector,what is the base current in $mA$?

In an $NPN$ transistor,$10^{8}$ electrons enter the emitter in $10^{-8} \ s$. If $1\%$ of electrons are lost in the base,the fraction of current that enters the collector and the current amplification factor are respectively:

In a $P-N-P$ transistor,the emitter has ....... as majority carriers and the base has ....... as majority carriers.

In a common-emitter transistor amplifier,$\beta = 50$ and the input resistance is $1 \ k\Omega$. If the peak value of the $AC$ input voltage is $0.01 \ V$,then the peak value of the $AC$ collector current will be .......

While a collector to emitter voltage is constant in a transistor, the collector current changes by $8.2 \,mA$ when the emitter current changes by $8.3 \,mA$. The value of forward current ratio is

$A$ transistor is used as a common emitter amplifier with a load resistance $2 \ k\Omega$. The input resistance is $150 \ \Omega$. The base current is changed by $20 \ \mu A$,which results in a change in collector current by $1.5 \ mA$. The voltage gain of the amplifier is