In a common-emitter transistor amplifier,$\beta = 50$ and the input resistance is $1 \ k\Omega$. If the peak value of the $AC$ input voltage is $0.01 \ V$,then the peak value of the $AC$ collector current will be .......

For a $CE$ transistor amplifier,the audio signal voltage across the collector resistance of $2.0\,k\Omega$ is $2.0\,V$. Suppose the current amplification factor of the transistor is $100$. What should be the value of $R_B$ (in $k\Omega$) in series with $V_{BB}$ supply of $2.0\,V$ if the $dc$ base current has to be $10$ times the signal current?

In a common emitter transistor circuit,the base current is $40 \ \mu A$. Find the value of $V_{BE}$. (in $V$)

$A$ transistor is operated in common emitter configuration at a constant collector voltage $V_C = 1.5 \, V$ such that a change in the base current from $100 \, \mu A$ to $150 \, \mu A$ produces a change in the collector current from $5 \, mA$ to $10 \, mA$. The current gain $\beta$ is:

$A$ transistor having $\alpha = 0.99$ is used in a common base amplifier. If the load resistance is $4.5 \, k\Omega$ and the dynamic resistance of the emitter junction is $50 \, \Omega$,the voltage gain of the amplifier will be:

For a transistor,$\beta = 100$. The value of $\alpha$ is