$A$ transistor is used as an amplifier in a common-base configuration. The load resistance is $5 \text{ k}\Omega$, the current gain is $0.98$, and the input resistance is $70 \Omega$. The voltage gain and power gain are, respectively:

In an $N-P-N$ transistor,when does the current flow?

In an $n-p-n$ transistor,$10^{8}$ electrons enter the emitter in $10^{-8} \,s$. If $1\%$ of electrons are lost in the base,the fraction of current that enters the collector and the current amplification factor $\beta$ are respectively:

In a common emitter $(CE)$ amplifier having a voltage gain $G$,the transistor used has a transconductance of $0.03\,mho$ and a current gain of $25$. If the above transistor is replaced with another one with a transconductance of $0.02\,mho$ and a current gain of $20$,the new voltage gain will be:

$A$ $npn$ transistor is connected in common emitter configuration in a given amplifier. $A$ load resistance of $800 \,\,\Omega$ is connected in the collector circuit and the voltage drop across it is $0.8 \,\, V$. If the current amplification factor is $0.96$ and the input resistance of the circuit is $192 \,\,\Omega$,the voltage gain and the power gain of the amplifier will respectively be

$A$ common emitter amplifier has a voltage gain of $50$,an input impedance of $100\; \Omega$,and an output impedance of $200\; \Omega$. The power gain of the amplifier is: