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Question

(B) The voltage gain $(A_v)$ of an amplifier is given by the product of the current gain $(\beta)$ and the ratio of output impedance $(R_{	ext{out}})

Vedclass · Accepted Answer

$1250$

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(B) The voltage gain $(A_v)$ of an amplifier is given by the product of the current gain $(\beta)$ and the ratio of output impedance $(R_{	ext{out}})$ to input impedance $(R_{	ext{in}})$:$A_v = \beta 	imes \frac{R_{	ext{out}}}{R_{	ext{in}}}$Given $A_v = 50$,$R_{	ext{in}} = 100\; \Omega$,and $R_{	ext{out}} = 200\; \Omega$,we can find the current gain $(\beta)$:$50 = \beta 	imes \frac{200}{100}$$50 = \beta 	imes 2$$\beta = 25$The power gain $(A_p)$ is defined as the product of the current gain $(\beta)$ and the voltage gain $(A_v)$:$A_p = \beta 	imes A_v$$A_p = 25 	imes 50 = 1250$

$A$ common emitter amplifier has a voltage gain of $50$,an input impedance of $100\; \Omega$,and an output impedance of $200\; \Omega$. The power gain of the amplifier is:

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