The output characteristics of a transistor in common emitter $(CE)$ mode is the graph obtained by plotting

  • A
    $I_C$ against $V_{BE}$ at constant $I_B$
  • B
    $I_C$ against $I_B$ at constant $V_{BE}$
  • C
    $I_C$ against $V_{CE}$ at constant $I_B$
  • D
    $I_C$ against $I_B$ at constant $V_{CE}$

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In the $CB$ mode of a transistor, when the collector voltage changes by $0.5 \ V$, the collector current changes by $0.05 \ mA$. What is the output resistance in $k\Omega$?

The voltage gain of a transistor in common emitter configuration is $160$. The resistances in base and collector sides of the circuit are $1 \text{ k}\Omega$ and $4 \text{ k}\Omega$ respectively. If the change in base current is $100 \mu A$, then the change in output current is:

$A$ transistor is operated in common-emitter configuration at $V_{CE} = 2\, V$ such that a change in the base current from $100\,\mu A$ to $200\,\mu A$ produces a change in the collector current from $5\, mA$ to $10\, mA$. The current gain is

In the study of a transistor as an amplifier,if $\alpha = \frac{I_{C}}{I_{E}}$ and $\beta = \frac{I_{C}}{I_{B}}$,where $I_{C}$,$I_{B}$,and $I_{E}$ are the collector,base,and emitter currents respectively,then:

For a given transistor,if $\alpha = I_C / I_E = 0.96$,then the current gain $\beta$ is:

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