For a given transistor,if $\alpha = I_C / I_E = 0.96$,then the current gain $\beta$ is:

In the following transistor circuit,$R_i$ is the input resistance and $R_0$ is the output resistance. The approximate voltage gain for the circuit is:

An $N-P-N$ transistor in a common emitter mode is used as a simple voltage amplifier with a collector current of $4 \ mA$. The terminal of an $8 \ V$ battery is connected to the collector through a load resistance $R_L$ and to the base through a resistance $R_B$. The collector-emitter voltage $V_{CE} = 4 \ V$,base-emitter voltage $V_{BE} = 0.6 \ V$ and base current amplification factor $\beta_{d.c.} = 100$. Calculate the values of $R_L$ and $R_B$.

For a transistor,current gain $(\beta) = 50$. To change the collector current by $350 \mu A$,the base current should be changed by:

$10^{10}$ electrons enter the emitter of a junction transistor in a time of $0.4 \mu s$. If $5 \%$ of the electrons are lost in the base, then the collector current is (in $\text{ mA}$)

For a common emitter configuration,if $\alpha$ and $\beta$ have their usual meanings,the incorrect relationship between $\alpha$ and $\beta$ is: