$10^{10}$ electrons enter the emitter of a junction transistor in a time of $0.4 \mu s$. If $5 \%$ of the electrons are lost in the base, then the collector current is (in $\text{ mA}$)

In a common-emitter transistor amplifier,$\beta = 50$ and the input resistance is $1 \ k\Omega$. If the peak value of the $AC$ input voltage is $0.01 \ V$,then the peak value of the $AC$ collector current will be .......

In the study of a transistor as an amplifier,if $\alpha = \frac{I_{C}}{I_{E}}$ and $\beta = \frac{I_{C}}{I_{B}}$,where $I_{C}$,$I_{B}$,and $I_{E}$ are the collector,base,and emitter currents respectively,then:

For a common-emitter amplifier, the voltage gain is $40$. Its input and output impedances are $100 \ \Omega$ and $400 \ \Omega$, respectively. The power gain of the $CE$ amplifier will be

In the given common emitter transistor circuit,the base current is $I_B = 40 \, \mu A$. Determine the base-emitter voltage $V_{BE}$. (in $, V$)

An $n-p-n$ transistor can be considered to be equivalent to two diodes connected back-to-back. Which of the following figures is the correct one?