An n-p-n transistor can be considered to be e | vedclass

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(B) An $n-p-n$ transistor consists of two $p-n$ junctions. In an $n-p-n$ transistor,the emitter-base junction is a $p-n$ junction and the collector-ba

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(B) An $n-p-n$ transistor consists of two $p-n$ junctions. In an $n-p-n$ transistor,the emitter-base junction is a $p-n$ junction and the collector-base junction is also a $p-n$ junction. The base is the common $p$-type region. For an $n-p-n$ transistor,the emitter is $n$-type,the base is $p$-type,and the collector is $n$-type. This means the emitter-base diode has its $n$-side at the emitter and $p$-side at the base. The collector-base diode has its $n$-side at the collector and $p$-side at the base. Therefore,the two diodes are connected with their cathodes (n-sides) facing outwards and their anodes (p-sides) connected together at the base. Looking at the provided figures,option $B$ correctly shows two diodes with their anodes connected at the base $B$ and cathodes pointing towards the emitter $E$ and collector $C$ respectively.

An $n-p-n$ transistor can be considered to be equivalent to two diodes connected back-to-back. Which of the following figures is the correct one?

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