What is the voltage gain in a common emitter amplifier,where input resistance is $3 \, \Omega$ and load resistance is $24 \, \Omega$,and the current gain $\beta = 0.6$?

For a transistor amplifier in a common-emitter configuration,given the load resistance $R_L = 1 \ k\Omega$,$h_{fe} = 50$,and $h_{oe} = 25 \ \mu A/V$,calculate the current gain $(A_i)$.

For a given transistor,if $\alpha = I_C / I_E = 0.96$,then the current gain $\beta$ is:

For a transistor,current gain $(\beta) = 50$. To change the collector current by $350 \mu A$,the base current should be changed by:

Which two of the following statements are true for a transistor?
$(1)$ The base,emitter,and collector regions of a transistor have the same size and doping concentration.
$(2)$ The base region is thin and lightly doped.
$(3)$ The emitter-base junction is forward-biased,and the base-collector junction is reverse-biased.
$(4)$ Both the emitter-base junction and the base-collector junction are forward-biased.

The correct relationship between $\alpha$ and $\beta$ for a transistor is ........